Question: calculus question 3. The hyperbolic function f (x) = ez - = sinh (x) is one-to-one function, and hence the inverse 2 function f (x)

 calculus question 3. The hyperbolic function f (x) = ez -

calculus question

= sinh (x) is one-to-one function, and hence the inverse 2 function

3. The hyperbolic function f (x) = ez - = sinh (x) is one-to-one function, and hence the inverse 2 function f (x) = sinh (x) exists. Determine sinh (x) as an explicit expression in terms on the natural logarithm of x, and also find the derivative of sinh (x)

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