Question: Call a metric space sequentially compact if every sequence has a convergent subsequence. Prove that a metric space is sequentially compact if and only if

 Call a metric space sequentially compact if every sequence has a

convergent subsequence. Prove that a metric space is sequentially compact if and

Call a metric space sequentially compact if every sequence has a convergent subsequence. Prove that a metric space is sequentially compact if and only if every infinite subset has a cluster point.

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