CAN ANYONE HELP ME PLEASE! THUMBS UP WILL BE GIVEN!! THANKS

2.1 Use a text editor to enter the program on textbook page 47 (the code is given here for your convenience). Use GNU GCC to compile, debug (find and fix any syntax errors), and execute the program and fix any semantic errors, for example, by adding "break" statements in the required places and by fixing incorrect characters copied into the programming environment, if any, and by type-changing to print a floating point number. The code is supposed to perform one math operation in each switch-case. The ch' variable is assigned a new math operator before each switch-case. Submit the corrected program as hw01q2.c [8 points] /* This C program demonstrates the switch statement without using breaks. */ #include main) char ch int a 10, b20; double f; printf("ch-%c ", ch); switch (ch) ( case '+': f- a + b; printf("f-%d ", case '-': f- a - b; printf("f-%d ", case '*': f- a * b; printf("f-%d ", case '/': f- a / b; printf("f-%d ", default: printf("invalid operator "); f); f); f); f); printf("ch-%c ", ch); switch (ch) ( case '+': f- a + b; printf("f-%d ", case '-': f- a - b; printf("f-%d ", case '*': f- a * b; printf("f-%d ", case '/': f- a / b; printf("f-%d ", default: printf("invalid operator "); f); f); f); f); printf("ch-%c ", ch); switch (ch) ( case '+': f- a + b; printf("f-%d ", case '-': f- a - b; printf("f-%d ", f); f case : f - a * b; printf("f-%d ", case ./. : f -a / b; printf("f-%d ", default: printf("invalid operator "); f); f); ch printf("ch-%c ", ch); switch (ch) case '+': f a + b; printf( "f-%d ", case '-': f a - b; printf("f-%d ", case '"': f - a * b; printf("f-%d ", case ./": f -a / b; printf("f-%d ", default: printf("invalid operator "); f); f); f); f); printf("ch-%c ", ch); switch (ch) { case +': f a + b; printf("f-%d ", case '-': f a - b; printf("f-%d ", case '"' : f a * b; printf("f-%d ", case '/. : f a / b; printf("f-%d ", default: printf("invalid operator "); f); f); f); f)