Question: Can I get help with the worst case time and space complexity of the following code please. In big - O notation preferably from collections

Can I get help with the worst case time and space complexity of the following code please. In big-O notation preferably
from collections import deque
class TreeMap:
def __init__(self, roads, solulus):
self.graph ={} # Initialize an empty graph
self.solulus ={} # Initialize an empty dictionary for Solulu trees
# Add roads to the graph
for road in roads:
u, v, w = road
if u not in self.graph:
self.graph[u]=[]
self.graph[u].append((v, w))
# Add solulus to the dictionary
for solulu in solulus:
x, y, z = solulu
self.solulus[x]=(y, z)
def escape(self, start, exits):
# Initialize queue with paths containing only the start node
queue = deque([(start,[start],0, False)]) # (node, path, time, solulu_broken)
# While there are paths to explore
while queue:
node, path, time, solulu_broken = queue.popleft()
# If the current node is an exit and a Solulu tree has been broken, return the path
if node in exits and solulu_broken:
return time, path
# Explore all neighbors
for neighbor, travel_time in self.graph.get(node,[]):
# If the neighbor is a Solulu tree
if neighbor in self.solulus:
solulu_destroy_time, teleport_destination = self.solulus[neighbor]
if not solulu_broken:
# Break the Solulu tree and continue
queue.append((teleport_destination, path +[teleport_destination], time + travel_time + solulu_destroy_time, True))
# Continue without breaking the Solulu tree
queue.append((teleport_destination, path +[teleport_destination], time + travel_time, solulu_broken))
else:
# Regular node traversal
queue.append((neighbor, path +[neighbor], time + travel_time, solulu_broken))
# If no valid path is found
return None
# Example 1
# The roads represented as a list of tuples
roads =[(0,1,4),(1,2,2),(2,3,3),(3,4,1),(1,5,2),
(5,6,5),(6,3,2),(6,4,3),(1,7,4),(7,8,2),
(8,7,2),(7,3,2),(8,0,11),(4,3,1),(4,8,10)]
# The solulus represented as a list of tuples
solulus =[(5,10,0),(6,1,6),(7,5,7),(0,5,2),(8,4,8)]
# Creating a TreeMap object based on the given roads
myforest = TreeMap(roads, solulus)
# Example 1.1
start =3
exits =[4]
print(myforest.escape(start, exits))

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