can somekne help me draw& figure out the compund for 4 and 5? Compound 4: 31.03/1599 C
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can somekne help me draw& figure out the compund for 4 and 5?
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Compound 4: 31.03/1599 C 2.749 H=2.49 MW: 206.20 C: 64.08 0: 31.03 H: 4.89 C NMR: 200 180 160 140 120 100 PPM 60 80 40 20 The "C NMR indicates the presence of 2 different carbonyls, including a ketone. Compound 5: MW: 110.16 C: 76.33 H: 9.15 0: 14.52 IR: 2203 cm' (medium), 1674 cm' (broad, strong) 'H NMR: singlet, 3H doublet, 6H septet, 1H alle 3 PPM 70.33/12.01 = 0.350/.908=7 9.15/1.01= 9.059/,908 = 10 14.52115.99=.908/.908 = Compound 4: 31.03/1599 C 2.749 H=2.49 MW: 206.20 C: 64.08 0: 31.03 H: 4.89 C NMR: 200 180 160 140 120 100 PPM 60 80 40 20 The "C NMR indicates the presence of 2 different carbonyls, including a ketone. Compound 5: MW: 110.16 C: 76.33 H: 9.15 0: 14.52 IR: 2203 cm' (medium), 1674 cm' (broad, strong) 'H NMR: singlet, 3H doublet, 6H septet, 1H alle 3 PPM 70.33/12.01 = 0.350/.908=7 9.15/1.01= 9.059/,908 = 10 14.52115.99=.908/.908 =
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Compound 4 now in this case the percentage of the element is given as C 6408 H 489 now O 100 6408 489 3103 now the let 100 g of compound is taken then ... View the full answer
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