Question: can someone explain this? and how do they get U1 = 0.703 and U2 = 0.297? Thank you a.k.a. The Inverse CDF transform method A

can someone explain this? and how do they get U1 = 0.703 and U2 = 0.297? Thank you

a.k.a. The Inverse CDF transform method A general method for generating random variates from U(0,1)'s generated by a PRNG Some intuition on the process ... U, -(0,1)= 0.703 0.8333 6 1 0.1666 5 x 2 3/6 --- 2/6 H 0.6666 4. 0.3333 Uz-(0,1) = 0.297 0.5 0 i 3 4 5 x = 5 6 x x = 2

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