Can someone help me solve step 2 please

Tutorial Exercise Two electrons repel each other with a force that varies inversely as the square of the distance between them. One electron is fixed at the point (2, 4). Find the work done in moving the second electron from (-2, 4) to (1, 4). Step 1 Assume that at any point of time, the electron to be moved is located at (x, y x $ 4 ). Step 2 The distance formula states that d2 = ( 12 - y 1 ) 2 + ( x 2 - x 1 )2. You have one electron fixed at the point ( , 4) and one with mobile position (x, 4). Let X 1 = X, X2 = , y 1 = , and yz = Find the square of the distance from the fixed electron. d2 = ( - 4) 2 + ( - x ) 2 -x) 2 Submit Skip (you cannot come back) Need Help? Read It Watch It