Can someone help me to answer this question, please and explain it.

This is calculus 1

The following work was shown to evaluate lim,_,+ (tan 2x)". There is at least one mistake in the work. Identify the line where the FIRST mistake is made. 1. lim,-0+ (tan 2x) ? - 00 2. y = lim,-o+ (tan 2x)" Iny = limz-0+ x . In(tan 2x) - 0. (-co) 2 sec2 (21) 3. In y = limo+ In(tan 2x) = by L'Hop = lim,-o+ tan(21) 4. = lim,-0+ 2 sec' (2x) 2.1 tan(2x) 0 = OO 5. - Iny = 0o y = limx_o+ (tan 2x) = co 0 4 0 5 0 3 0 2 O 1