Question: Can someone help Solve the differential equation d2 d+2 + 16x =0 subject to the initial conditions that when t = 0, x = -4

Can someone help

Can someone help Solve the differential equation d2 d+2 + 16x =0

Solve the differential equation d2 d+2 + 16x =0 subject to the initial conditions that when t = 0, x = -4 and d at -x = 2. The answer, expressed as a linear combination of circular trig functions, is Which looks like 4- 3 x 2- 1 0 4 18 -1 -2 -3

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