Question: Can someone please explain how these were computed? They have already been answered A box of 7 cellphones contains three yellow cellphones and four green

Can someone please explain how these were computed? They have already been answered

A box of 7 cellphones contains three yellow cellphones and four green cellphones_ Complete parts (a) through (d) below. a. If nvo cellphones are randomly selected from the box without replacement, what is the probability that both cellphones selected wiil be green? P(both green) - 0.2857 b. If cellphones are randomly selected from the box without replacement, what is the probability there will be one green cellphone and one yellow cellphone selected? PCI green and 1 yellow) 0.5714 c. If three cellphones are selected with replacement (the first cellphone is retumed to the box after it is selected), what is the probability that all three will be yellow? P(three yellow) = 0.0787 d. If you were sampling With replacement (the first cellphone is returned to the box aner is selected), what would be the answers to (a) and (b)? P(both green) - 03265 PCI green and 1 yellow) 0.4898

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