Can someone please explain why the attempt 2 is incorrect. the first question remains the same so the answers should be the same. Being a one sided alternative for attempt 2 i thought the p value was 4/10 = 2/5. I am a little confused as to why i got it wrong.

Name: Quiz 17, Attempt 1 Five students take an IQ test. Three subjects were on placebo and two were on NZT when taking the test. Their scores are reported below. Use a permutation test (test statistic = difference in means) in order to determine if NZT improves IQ. Specifically, test the null hypothesis that the distributions are identical against a two-sided alternative. NZT 102 96 Placebo 120 90 2 84 120 102 96 90 84 t X 21 x 16 X 6 p-value : 2 .50 = 1 Repeat this problem using the rank-sum test. 7 3 4 5 P-value :Quiz 17, Attempt 2 Five students take an IQ test. Three subjects were on placebo and two were on NZT when taking the test. Their scores are reported below. Use a permutation test (test statistic = difference in means) in order to determine if NZT improves IQ. Specifically, test the null hypothesis that the distributions are identical against a one-sided alternative (NZT improves IQ). NZT Placebo 102 96 120 90 84 P- value = 2 . 5 = 1 Repeat this problem using the rank-sum test. 3 4 5 X X X to puvalve = x XXX X X X X X X