Can someone solve these missed problems please I'm lost!

In the figure, an electron accelerated from rest through potential difference V1=1.11 kV enters the gap between two parallel plates having separation d = 22.0 mm and potential difference V2= 71.8 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? d Number ( 0 it 0 + 0.165 k ) Units mT V e Textbook and Media Hint Save for Later Attempts: 2 of 3 used Submit AnswerA proton travels through uniform magnetic and electric elds. The magnetic eld is in the negative X direction and has a magnitude of 2.59 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2250 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric eld is (a) in the positive 2 direction and has a magnitude of 4.60 V/m, (b) in the negative 2 direction and has a magnitude of 460 V/m, and (c) in the positive x direction and has a magnitude of 4.60 Wm? (c) Number Units Your answer is partially correct. The figure shows a metallic block, with its faces parallel to coordinate axes. The block is in a uniform magnetic field of magnitude 0.018 T. One edge length of the block is 24 cm; the block is not drawn to scale. The block is moved at 2.1 m/s parallel to each axis, in turn, and the resulting potential difference V that appears across the block is measured. With the motion parallel to the y axis, V =18 mV; with the motion parallel to the z axis, V= 12 mV; with the motion parallel to the x axis, V = 0. What are the block lengths (a) dx, (b) dy, and (c) dz ? X dz dx 2 (a) Number 0.24 Units m (b) Number i 0.476 Units m (c) Number i 0.317 Units m