Can someone translate this C program to MIPS assembly? I'm only interested in the forming the union in one register part, not counting the size of the union.

28 29 int SetA[] int SetB[] = {5, -19, 26, -63, 18, 26, 8, 3, 6, -9, 17, 17, 25, 12, -63); -9, 60); 60, {8, 11, nt main() { 31 32 int Size; int counter 0; 34 int lenA 10; 35 int lenB 10; 36 for (int -0; ilenA; 1++){ for (int x = 0; xaenBX++){ if (SetAi] SetB[x]) 38 39 40 SetA[i]-SetA[i+1]; i+-1; lenA 1; 46 counter1; printf("%d : %d ", counter, SetA[1]); s0 insert your code here 51 print thei_th element of the union set using a print stotement with this format: 52 // printf("%d: %d ", i, element); 53 Size-counter+10; 54 printf("Union Set Size: %d ", size); return 0; 57