can you answer my previous question using this as an example: Two ships leave a harbor at the same time. One ship travels on a bearing Upper S 16 degrees Upper W at 19 miles per hour. The other ship travels on a bearing Upper N 75 degrees Upper E at 14 miles per hour. How far apart will the ships be after 3 hours? Question content area bottom Part 1 The Law of Cosines If A, B, and C are the measures of the angles of a triangle, and a, b, and c are the lengths of the sides opposite these angles, then a squared equals b squared plus c squared minus 2 bc cosine Upper A b squared equals a squared plus c squared minus 2 ac cosine Upper B c squared equals a squared plus b squared minus 2 ab cosine Upper C The square of a side of a triangle equals the sum of the squares of the other two sides minus twice their product times the cosine of their included angle. Part 2 Determine how far the ship traveling SW traveled. 19 mph times 3 hrs equals 57 mi Part 3 Determine how far the ship traveling NE traveled. 14 mph times 3 hrs equals 42 mi Part 4 Determine the angle between the paths taken by the ships. 15 degrees plus 90 degrees plus 16 degrees equals 121degrees Part 5 Use the Law of Cosines to determine the distance between the ships. d squared equals left parenthesis 57 right parenthesis squared plus left parenthesis 42 right parenthesis squared minus 2 left parenthesis 57 right parenthesis left parenthesis 42 right parenthesis left parenthesis cosine left parenthesis 121 degrees