Question: can you explain your calculations and steps as much possible please! thanks! 1. 5000kg of saturated solution of KAl(SO4)2 is cooled from 80C to 20C
can you explain your calculations and steps as much possible please! thanks!
1. 5000kg of saturated solution of KAl(SO4)2 is cooled from 80C to 20C in a crystalliser. The KAl(SO4)2 crystallises as a dodecahydrate, i.e. as KAl(SO4)212H2O settling in the tank and being discharged through the bottom. The overflow is a saturated solution at 20C. The solubility of KAl(SO4)2 is 51.5%(w/w) at 80C and 5.7%(w/w) at 20C. Calculate the amount of KAl(SO4)2 crystals obtained (non-hydrated basis). M(KAl(SO4)2)=258.21gmol1,M(KAl(SO4)2.12H2O)=474.39gmol1
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