Question: Can you help fix this function to make it work using pass by reference? The function I am trying to use is the square of

Can you help fix this function to make it work using pass by reference? The function I am trying to use is the square of a number. For example, 4^2 or 4 x 4 = 16. The code should be C++. Thank you.

#include using namespace std;

void square(int &x);

int main() { int integer; cout << "Enter an integer: " << endl; cin >> integer; }

void square(int &x) { int square; square = x * x; cout << "The square of the integer is: " << square << endl; }

6.5.0

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