Can you help me answer the bold sections based on the graphs?

The ANOVA requires that the assumption of normality be met. Normality was examined using Shapiro-Wilks. The assumption of normality wasmetot met. See Table 2 for Tests of Normality.

DELETE Std. N Minimum Maximum Mean Deviation tude Scores 5 7 5.83 .983 d N (listwise) Middle Attitude Scores 5 9 7.50 1.378 Valid N (listwise) High Attitude Scores 8 6.00 1.414 Valid N (listwise)Kolmogorov-Smirnov Shapiro-Wilk DELETE Status Statistic df Sig. Statistic df Sig. es Low 302 6 094 .775 6 .035 Middle .308 6 077 857 O .178 High 167 6 200' 982 960 *. This is a lower bound of the true significance. a. Lilliefors Significance CorrectionLevene DELETE Statistic df1 df2 Sig. Based on Mean 102 NJ 15 904 Based on Median .068 15 934 Based on Median .068 2 11.480 934 and with adjusted of Based on trimmed .089 2 15 .915 mean Tests the null hypothesis that the error variance of the dependent variable is equalariable: Attitude Scores DELETE Type Ill Sum Mean Partial Eta of Squares df Square F Sig. Squared del 10.111a 2 5.056 3.116 .074 294 Intercept 747.556 1 747.556 460.822 000 .968 Status 10.111 2 5.056 3.116 074 294 Error 24.333 15 1.622 Total 782.000 18 Corrected Total 34.444 17 a. R Squared = .294 (Adjusted R Squared = . 199)I LU DELETE Mean 95% Confidence Interval lifference Lower Upper ( I-J) Std. Error Sig. Bound Bound -3666.67 3044.728 .469 -11575.26 4241.92 24333.33' 3044.728 000 16424.74 32241.92 Zna Ist 3666.67 3044.728 .469 -4241.92 1 1575.26 3rd 28000.00' 3044.728 .000 20091.41 35908.59 3rd 1st -24333.33' 3044.728 000 -32241.92 -16424.74 2nd -28000.00 3044.728 000 -35908.59 -20091.41