Can you help me answer the question by using my material that shows on pictures? Can you show the calculation for finding the answer?

**using p-value method**

146-3 neshey's revisited If the machine isn't working at top capacity, you will need to have it replaced. 146-4 neshey's revisited The hourly output of the machine is normally distributed, Before the flood, the machine wrapped an average of 340 Smooches per hour. Over the first week after the flood, you counted wrapped Smooches during 32 randomly selected one-hour periods. The machine averaged 318 Smooches per hour, with a standard deviation of 44. Null Hypothesis Mean 340 Null Hypothesis ? Alternative Hypothesis ? Sample Size (n) 32 Sample Mean (x) 318 Sample Std. Dev. (s) 44 Confidence Level 95% Question 146-5 neshey's revisited You conduct a one-sided hypothesis test using a 95%confidence level. According to your calculations, you should: A. Replace the machine. 6.Keep the machine. Null Hypothesis Mean 340 Null Hypothesis ? Alternative Hypothesis ? Sample Size (n) 32 Sample Mean (x) 318 Sample Std. Dev. (s) 44 Confidence Level 95%146-8 neshey's revisited This z-value corresponds to a left-tail probability of 0.0023. This is the tail you are interested in, since you are conducting a one-sided to test to see if the actual population mean is less than it was in the past, This tail probability is the p-value. 0.0023 -2.83 146-9 neshey's revisited Since the p-value is less than the significance level, you reject the null hypothesis that the population mean is unchanged. Moreover, you now can say that you are rejecting the null hypothesis at the 0.0023 level of significance. You should replace the machine. 0.0023