Can you help me solve this problems please and make sure they are in the right significant Figures too also this is the problem for them too. When 4.89 g of solid NaOH was dissolved in 47.92 g of water in an adiabatic calorimeter at 24.7C, the temperature of the solution went up to 50.1C.

108 Experiment 14 Heat Effects and Calorimetry b. Calculate q1 0, using Equation 1. 6= CXMXAT a s ( 4 183 19- 25) ( 47. 92 9) 6 24.706-50.100) ( 4. 18 3 /13- 8) ( 4 7. 92 g) (= 25,402) = -5087. 76274 -5,04 X joules Use Equation 5 to calculate AH for the dissolution reaction as it -5-09x163 occurred in the calorimeter, AH solution- - 6.09 x 103 =+5.09x103 AH solution = 5.04 x103 _joules d. Find AH for the dissolution of 1.00 g of solid NaOH in water, AH solution- AH solution KJ/g e. Find AH for the dissolution of 1 mole of solid NaOH in water, AHsolution- AH solution = kJ / mol f. Given that NaOH exists as Na and OH ions in solution, write the equation for the reaction that occurs when solid NaOH is dissolved in water. g. Given the heats of formation, AH,, listed in Table 14.1, calculate AHreaction for the dissolution reaction in Part (f). Compare your answer with the result you obtained in Part (e). Table 14.1 Selected Molar Enthalpies of Formation, AH, Substance AH, {k.J/mol} NaOH(s) -425.6 Na(aq) -240.1 kJ /mol OH (aq) -230.0 AHreaction