Can you please answer the question from your own work with details for good feedback

T. Solve the integral a] using partial fractious. b] without using partial fractions For part b. to solve this integral without partial fractions, try a usubstitution. u=x2 du=dx 8. Evaluate the integral I 3x3 + 1 a x052 + 1)2 x Notice the x2 + 1 in the denominator. [t is called an irreducible quadratic Itis a seconddegree polynomial that cannotbe factored. When the denominator involves an irreducible quadratic. we cannot just assume that its partial fractions will all have constant numerators. We have to allow for the possibility that the numerator involves an x. The correct separation of fractions is given below. Use this to solve the integral. 3x3+1 A Bx+C Dx+E x = + + x(x2 + 1)2 x2 + 1 (x2 + 1F