Can you please choose the correct answer

arrival time Bust time pl for the above table, under FCFS scheduling, processes are scheduled as follows: a. pl, p4, p2, p3 b. pl, p2, p4, p3 c. pl, p2, p3, p4 d. p2, p4, p3, pl arrival time Bust time 13 for the above table, under SJF scheduling, processes are scheduled as follows c. d. p3, pl, p4, p3 X pl, p3, p4, p2 pl, p3, p2, arrival time Bust time 13 for the above table, under round robin (with time quantuam equals 4) scheduling a. Average waiting time equals 10 c. process 4 finishes its burst before d. none of the above b. Average response time equals 15 . OS estimates the next CPU burst for SJF scheduling by using an equation like 0 20 37 57 77 97 117 121 134 154 for the above gant chart, using round robin scheduling a. P1 burst time equals 44 b. time quantum equals 17 162 p3 burst equals 57 p4 is less than pl in burst time c. d