Can you please explain this to me step by step. I don't understand how you get the intervals and the answers in general.

Consider the sample of 65 customer satisfaction ratings given in the table (below). 44 44 44 45 39 46 42 40 45 46 46 45 44 46 46 46 41 48 39 38 40 40 41 43 38 43 47 43 41\\ 42 39 44 39 43 36 44 42 40 44 45 42 41 42 41 44 44 47 38 45- 45 46 40 45 43 44 43 42 Click here for the Excel Data File Carry out a chi-square goodness-of-fit test of normality for the population of all customer satisfaction ratings using a = .05. Recall that we previously calculated a = 42.95 and s = 2.6424 for the 65 ratings. Use the Empirical Rule to create the intervals. (Round your expected frequencies to 2 decimal places. Round your answer to 3 decimal places.) a normal distribution. X1 2 = : so HO. normality. Conclude population Answer : Given : x= 49.95, 5=2. 6424 and 1=65 Interval RX Fi E: GER-ELIO ( Fi - E: ) 2 0. 0928 ( 65 ) = 1.482 0 . 15676 x + 25 ( 48.235, 00) 0 . 0228* 65 = 1.482 1.482 Sum Teststatistic: 72 & ( Fi - EI ) 2 10 07401 Ei = 10 . 074 D.P = 3 , 2 = 0 05 cortical value ( R 2 ) = CHINNY ( 0. 05 . 3) = 7.815 since, Real = 10.074 7 72 c= 7-815. so, wereject Ho. Normally conclude population not a normal distribution