Can you please help me solve this calculus question. I tried my best but I don't understand. I think I got d2x/dt^2 correct but that's about all I did right.

13.) For t 2 0 a particle is moving along a curve so that it position at time t is (x(t), y(t)). If it known that hat al = sin '(1-2e ' ) and dy = 4t for t 2 0. dt 1+1 a.) Find the horizontal and vertical acceleration of the object at time t = 2 dy 4 ( 1+ +) ) - 4+ ( 3+2 ) 17 - ( 1- 20 ) 0. 270671 4+ 8 8 = 0. 684163 96 = 0. 395624 81 = - 1.037 b.) The curve has a vertical tangent line at one point. At what time t is the object at this point. when + = . - 2 c.) Let m(t) denote the slope of the line tangent to the curve at the point (x(t), y(t)). Write an expression m(t) in terms of t and use it to evaluate lim m(t). 0of- 1 m k+ ) = m ( x ( + ) ) + b 4+ m ( + ) = OK sin ( 1-20 "+ ) (imm ( ) C