Question: can you please help me with this assignment, please show all the work. This is Physics 20 (grade 11)- Module 4- Lesson 1 Acceleration Due

 can you please help me with this assignment, please show allthe work.This is Physics 20 (grade 11)- Module 4- Lesson 1 AccelerationDue to GravityLAB LINK WITH PROCEDURE:https://phet.colorado.edu/sims/html/gravity-force-lab/latest/gravity-force-lab_en.html Question 1 This question is related

can you please help me with this assignment, please show all the work.

This is Physics 20 (grade 11)- Module 4- Lesson 1 Acceleration Due to Gravity

LAB LINK WITH PROCEDURE:

https://phet.colorado.edu/sims/html/gravity-force-lab/latest/gravity-force-lab_en.html

to the Gravity Simulation found in the lesson. CLICK HERE for Notyet the simulation. See the notes for Lesson 1 for instructions. answeredMarked out of a) As you move Mass 1 closer to Mass2, the gravitational force 4.00 Flag b) The gravitational force acting onMass 1 is equal to the gravitational force acting on Mass 2.

Question 1 This question is related to the Gravity Simulation found in the lesson. CLICK HERE for Not yet the simulation. See the notes for Lesson 1 for instructions. answered Marked out of a) As you move Mass 1 closer to Mass 2, the gravitational force 4.00 Flag b) The gravitational force acting on Mass 1 is equal to the gravitational force acting on Mass 2. question Why is this true? c) The largest value of the gravitational force, as displayed in the simulation is N. Enter using Scientific Notation or as a decimal. d) If you increase the value of Mass 1 to 200 kg instead of 100 kg you would expect the force of gravity to increase by what factor:The simulation shows the relationship between the force of gravity acting between two masses mass: the physical amount of matter that as a function of the separation distance. Adjust the simulation to match the following diagram: makes up an object Force on m2 by m1 = 2.67 x 10-8 N Force on m1 by m2 = 2.67 x 10-8 N .- - -- - - m1 m2 0 meters 1 2 3 5 6 8 9 10 Mass 1 Mass 2 Force Values 100 kg 400 kg Decimal Notation 10 1000 1000 O Scientific Notation Hidden Constant Size Note the following: 1) The length of the force vector is proportional to the strength of the gravitational force. 2) Make sure "Constant Size" is clicked "on". 3) You can move either mass, but I suggest you leave mass 2 stationary to simplify the procedure. 4) Make sure Mass 1 = 100 kg and Mass 2 = 400 kgfound in the lesson. CLICK HERE structions. onal force becomes weaker the gravi becomes stronger n Mass does not change ayed in the simulation isavitational force acting on Mass 1 is equal to the g is true V Because the masses are the same size. gest v Because of Newton's First Law. d i ing Sc Because of Newton's Second Law. Because of Newton's Third Law. increas f 1Question 2 Complete the following table using the simulation from Lesson 1. You can select whatever Answer saved locations you choose. Make sure you fill in the entire table. Marked out of 6.00 a) Complete the table. (3 marks) Flag b) Graph the data (Force of Gravity as a function of Separation Distance) and UPLOAD the question graph. (3 marks) Format B Distance Between Mass 1 and Mass 2 (m) Gravitational Force (N) Path: table

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