can you please please please work it out and show all the steps as well please use matlab to prove yohr answer

The mol fraction of a contaminant in a waste gas stream is 0.07. In order to meet environmental regulations, the mol fraction must be reduced to 0.001 or less before the waste gas is emitted to the atmosphere. A scrubber consisting of a simple absorption column will be used for this purpose. The scrubbing liquid entering the top of the column will have a contaminant mol fraction of zero, and the equilibrium ratio (K) for the contaminant is 0.7 1. If the scrubber is to contain 35 equilibrium stages, what is the largest gas to liquid (G/L) ratio that can be used? Note that the stages are numbered from bottom (1) to top (n). The mol fraction of contaminant in the gas stream leaving the scrubber is y. -Kx