can you put this answer into desmos for me?

The population of a culture of bacteria is modeled by the logistic equation

P(t)= \frac{14,250}{1+29e^{-0.62t}.

To the nearest tenth, how many days will it take the culture to reach 75% of its carrying capacity?

P(t) = 0.75 * carrying capacity

Carrying capacity = 14,250

0.75 * 14,250 = 10,687.5.

10,687.5 = 14,250 / (1 + 29 * e^(-0.62t)) for t.

Multiply both sides by (1 + 29 * e^(-0.62t))

Simplify and isolate e^(-0.62t) to get 0.1775

Take natural logarithm of both sides to get -0.62t = ln(0.1775)

Solve for t to get approximately 7.5 days

It will take about 7.5 days for the culture to reach 75% of its carrying capacity.