can you rewrite this code without using break,continue,return inside and outside the loop. Arbitary value $/$sentenial value cannot be used to control loop. For filling the card with unique numbers, you have to go through the BINGO card column by column $($rather than row by row

which is what we normally do for $2$D arrays$).$ Since the BINGO card has $5$ columns, this would be a good place to use a for loop.Repalce with these things

Now, for each column $($inside the for loop$),$ you need to find $5$ unique values that fit within the allowed range for that column.

So$,$ WHILE you haven't found all $5,$ get a random number in range, check if you have already gotten it in that column $-$ if you

have, throw it out and get another $-$ if you haven't, put it in your BINGO card.

So for the

$0$th column, your number needs to be $1-15$

$1$st column, your number needs to be $16-30$

$2$nd column, your number needs to be $31-45$

$3$rd column, your number needs to be $46-60$

$4$th column, your number needs to be $61-75$

We talked about generating a random number in a range by shifting the result from rand$()$

To get a value from $1-15$ rand$()\%15+1$

To get a value from $16-30$ rand$()\%15+16$

To get a value from $31-45$ rand$()\%15+31$

To get a value from $46-60$ rand$()\%15+46$

To get a value from $61-75$ rand$()\%15+61$

We can rewrite this as

To get a value from $1-15$ rand$()\%15+1$

To get a value from $16-30$ rand$()\%15+15+1$

To get a value from $31-45$ rand$()\%15+30+1$

To get a value from $46-60$ rand$()\%15+45+1$

To get a value from $61-75$ rand$()\%15+60+1$

This can be rewritten as

To get a value from $1-15$ rand$()\%15+(15*0)+1$

To get a value from $16-30$ rand$()\%15+(15*1)+1$

To get a value from $31-45$ rand$()\%15+(15*2)+1$

To get a value from $46-60$ rand$()\%15+(15*3)+1$

To get a value from $61-75$ rand$()\%15+(15*4)+1$

So you could use one statement

rand$()\%15+(15*$x$)+1$

to get random numbers in range for each column $($the x in the formula is the column number$/$index$).$