Question: Can you solve this please? Write a function that recursively computes 2 n (i.e. 1 multiplied by 2, n times) Assume positive n (n >=

Can you solve this please?

Write a function that recursively computes 2n (i.e. 1 multiplied by 2, n times)

Assume positive n (n >= 1).

def two_pow_n(n:int) -> int:

"computes 2**n for integer n > 0"

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