Question: Capa plays either one or two chess games every day, with the number of games that she plays on successive days being a Markov chain
Capa plays either one or two chess games every day, with the number of games that she plays on successive days being a Markov chain with transition probabilities
P1,1 = 0.2, P1,2 = 0.8, P2,1 = 0.4, P2,2 = 0.6.
Capa wins each game with probability p. Suppose she plays two games on Monday.
(a) (2 marks) What is the probability that she wins exactly one game on Tuesday?
(b) (3 marks) What is the expected number of games that she plays on Wednesday?
(c) (5 marks) In the long run, on what proportion of days does Capa win all her games?
Below is my own solution. Please verify if they are correct. I'm not too sure about the last question. Thank you!

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