Carry out the hand-simulation for the simple processing system in Chapter 2 using the following input (assume part 1 arrives at time 0; the unit is hour):

part number	Interarrival time (to the next part)	service time
1	1.5	0.5
2	0.6	1.2
3	0.4	0.8
4	1.2	1.1
5	0.8	0.7

The simulation will stop at exactly the time of 3 hours. (a) Please follow the same format as in Table 2-2 to show the results from each step of the simulation. (b) Based on the simulation results, calculate the average waiting time in queue, the timeaverage number of parts waiting in queue, and the utilization of the drill press.

Table 2-2. Record of the Hand Simulation ntity Time Event A rrival Times 0.00 A rr) 0.00ni 0 0.00 Ar 173 Ar 2.90 Depo 08 A rr 0.00 0.000.000.00 0.00 0.00 20.00End 1.73 [1. 2.90 A rr Dep] 0.00 0.00 0.00 0.00 0.00 .00 0.00 2.90 .08 3.08 (2, 4.66 3.79 (2. 4.66 1.73)0.00 0.00 0.00 0.00 0.00 0.00 1-73 A rr) [3 A rr D epl 1.73I 1.171172.90 2.90 1.1 2.90 A rr) D epl 3.08)73 1.171172.90 2.90 1.1 3.08 (s A rr) 2, 4.66 4.66 6 18.69 8.05 6, 8.69 .79Arr 3.79,3.08)1.73 1171172.90 2.908 3.79 Depl 4.41 Ar3 441,3.79,3.08) .73 1.171172.90 2.90 3.12 (3 Dep) A rr) 4.66 Dep2 4.41,3.79) 3.0 2.751585.83 2.93 3.8 4.66 2.57Depl (441)3.79 7.01 4.26 10.8049710.65 8.05 6.69 5 17.03Depl 412.57 Dep 01 4.4 51517816 19.58.7815.17 12.5 1 8.69 6, 18.69 19.39 A rr) A rr) A rr) 517.03 Dep 0 51517 816 32.2012.62 15.1 3 17.0 6 18.69Ar 0 18.69 6 15.17 816 32.20 12.62 15.1 17.0 20.00 End] 20.00End 719.39ArI 19.39) 18.69 6 151781632.20 12.62151 17.7 [6 23.05 20.00 End I 19.39)18.69 6 15.17 816 32.20 12.62 15.7 318.34 23.05