Cement (11ULE) Observations 1 2 3 4 5 Cycle 1 1.52 0.62 0.57 0.76 0.72 0.76 0.76 1.43 2.00 Cycle 2 Cycle 3 Cycle 4 Cycle 5 Cycle 6 Cycle 7 Cycle 8 Cycle 9 Cycle 10 Cycle 11 Cycle 12 Cycle 13 Cycle 14 Cycle 15 0.58 0.61 0.55 0.53 0.60 0.54 0.58 0.77 0.72 0.70 0.73 0.79 1.50 0.30 0.33 0.28 0.35 0.34 0.29 0.29 0.36 0.36 0.28 0.36 0.29 0.35 0.29 0.34 0.95 1.00 0.56 0.73 2.20 0.54 0.74 0.59 1.47 0.53 0.55 0.57 0.95 0.80 0.72 0.80 0.73 0.95 1.00 2.10 Rating Factor 1.10 0.35 0.90 0.25 Frequency 1.00 x your answer is incorrect. Try again. Using an allowance factor of 17.5 percent of job time, calculate the standard time for each element and for the entire job. (Round your answers to 3 decimal places, the tolerance is +/-0.001 and for Standard time for Job is +/-0.005.) ST element 1 = 3.083 minutes ST element 2 3.25 minutes ST element 3 4.064 minutes 1.741 ST element 4 = minutes ST element s = 2.7 U minutes Standard time for Job = L 14.844 minutes How many units should be completed each hour if the worker performs at 100 percent of the standard? (Round your answer to 3 decimal places, the tolerance is +/-0.001.) A worker should be able to perform 4.042 units per hour. units per LINK TO TEXT x Your answer is incorrect. Try again. How many units should be completed each hour if the worker performs at 106 percent of the standard? (Round your answer to 3 decimal places, the tolerance is +/-0.001.) A worker should be able to perform 4.285 units per hour