Question: . . CF 1 1 wan lab t ri filtresh n st di f k m t pan k nstant r epsi t .

.. CF11
wan labtri filtreshn stdi f kmt pan knstant r\epsi t. Di besik ikwyulet (Cook,1984) ikwyulet:
t
f
1999.
=[\Delta P.) we dn kl
c
1999.
WAN
2.2.
/\mu M
2.2.
c]x
c
1999.
exp(ax) we dn kl
c
1999.
+b).
Lel c
1.1.1.
1999.
=\Delta P
c
1999.
WAN
2.2.
/\mu M
2.2.
c
t
f
.
1999.
=c
1.1.1.
1999.
exp(ax) we dn kl
c
1999.
+b)(1aks) we dn kl
c
1999.
).
t
f
+
1999.
=ac
1.1.1.
1999.
(2aks) we dn kl
c
1999.
)ksp(aks) we dn kl
c
1999.
+b).
1999.
Nyutn mtd de gi x
c
k+1
1999.
=x
c
k
1999.
(i.)
f
.
1999.
,l
f
.
1999.
) usay t
f
1999.
= t\epsi m f bil op filta kek, min \Delta P
c
1999.
= prshn drp aks kek, psig (20) A= filtreshn eria, ft
2.2.
(250)\mu = filtrat viskositi, sntipyz (20) M= mas flf filtrt,1b
m
1999.
/min(75) c= slid knsntreshn insay fid f filta, Ib
m
1999.
/lbwe filt\epsi t (0.01) x
c
1999.
= mas frakshn slid dn na dray kek a= knstant rilayt kek rsistns to slid frakshn (3.643) h= knstant rilayt kek rsistns to slid frakshn (2.680)\beta =3.2\times 10
8
(lbuift we de na di wl
2.2.
).
2.2.
Dn gi nmba valyu fni paramita insay brakt. Obtain di maksimal t\epsi m f filtr\epsi shn as fnshn f x
c
1999.
bay wan numrik yunidimnshnal sch.

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