Question: CHALLENGE ACTIVITY 3 . 1 . 2 : Numeric types: Floating - point. 5 5 8 6 5 0 . 4 1 7 5 6

CHALLENGE
ACTIVITY
3.1.2: Numeric types: Floating-point.
558650.4175648.9x3zqy7
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A polynomial is given by p=10.0v2+8.0v-3.5. Read v from input as a float and compute p using the polynomial. Ex: If the input is 2.6, then the output is:
84.900
Note: v2 can be computed using *.
1
''' Your code goes here
3v= float(input())
4p=10.0**(v****2)+8.0(v)-3.5
5pr(f'{p:.3f}')
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CHALLENGE ACTIVITY 3 . 1 . 2 : Numeric types:

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