Question: Change the Cartesian integral into an equivalent polar integral. Then evaluate the polar integral. 1 1- y ( x2 + y? ) dx dy 0

 Change the Cartesian integral into an equivalent polar integral. Then evaluate

the polar integral. 1 1- y ( x2 + y? ) dx

Change the Cartesian integral into an equivalent polar integral. Then evaluate the polar integral. 1 1- y ( x2 + y? ) dx dy 0 0 . . . Change the Cartesian integral into an equivalent polar integral. 1 V1 -y2 (x2 + y?) ax dy= J dr de 0 0 The value of the polar integral is (Type an exact answer, using it as needed.)

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