Charge A $(-4\mathrm{.}03$ nC$)$ is placed $0\mathrm{.}400$ m away from charge B $(3\mathrm{.}31$ nC$).$ What is the electric field strength at a position $0\mathrm{.}50$ of the distance from charge A to charge B$?$ Consider the positive direction to be left$-$to$-$right, and give your answer in N$/$C to one decimal place.