ChatcpT

Certainly, here are the steps with solutions:

Convert to Binary

$13\mathrm{.}2543{?}^{}1101\mathrm{.}01000001000110011100.$

$0\mathrm{.}0567-0\mathrm{.}00001110100000111110$

Normalize the Numbers

$13\mathrm{.}2543$: $\text{'}1\mathrm{.}101010000010001100111002^{{?}^{{?}^{?}}}3$

${0\mathrm{.}05677}^{}1\mathrm{.}1101000001111102^{{?}^{{?}^{?}}}-5^{.}$

Align the Exponents

$13\mathrm{.}2543$: $\text{'}1.101010000010001100111002^{{?}^{{?}^{?}}}3$

$*0\mathrm{.}0567$ aligned: $*0\mathrm{.}000000001110100000111112^{{?}^{{?}^{?}}}$

Add the Mantissas

$1\mathrm{.}10101000001000110011100.$

cdots$+0\mathrm{.}00000000111010000011111.$

Result: $\text{'}1101,01001111100111011010.$

Normalize the Result

Already normalized: $\text{'}1101,01001111100111011010\text{'}$

Convert Binary to Decimal

Resultin decimal: $13\mathrm{.}3110$

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