Question: Check digit . program CheckDigit.java that takes a 12 or 13-digit long as a command-line argument and displays the digit computed as follows: Please leave

  1. Check digit . program CheckDigit.java that takes a 12 or 13-digit long as a command-line argument and displays the digit computed as follows: Please leave step by step comments for me to understand what your doing each steps.
    • Take for an example the number 048231312622
    • Sum every other digit of the code, starting from the right. In the example, that is 2+6+1+1+2+4=16. Discard the tens digit and keep the ones digit, 6.
    • Start with the second to last digit and do the same thing. Sum the digits, discard the tens digit and keep the ones digit. In this example this is 2+2+3+3+8+0=18. Discarding the 10 leaves 8. Multiply this number by 3 and again discard the tens digit. 83=24, leaving 4.
    • Add the numbers from steps 1 and 2. Again drop the tens digit. 6+4=10, leaving the digit 0 (zero).
    • Hint 1: the maximum value that can be stored in an integer variable is 2147483647 which is only 10 digits long. To read a 12 or 13-digit integer from command line argument you will need to store it in a long variable. Use: long number = Long.parseLong(args[0]); to read a long from the command line.
    • Hint 2: to extract the rightmost digit of a number use the modulus operator.
    • Hint 3: to remove the rightmost digit of a number use the integer division by 10
    • Hint 4: for full credit use a loop to compute the sums
  • Assume the input value used to test your program is a 12 or 13-digit positive integer.

java CheckDigit048231312622 0

java CheckDigit9780470454310 8

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