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1 Data Table and Linear Optimization Model X Components Required/Unit A B Profit/Unit LaserStop 18 125 Speedbuster 13 137 After reviewing the components required and the profit for each model, the firm found the following linear optimization model for profit, where L is the number of LaserStop models produced and S is the number of SpeedBuster models produced. Maximize Profit = 125 L + 137 S 18 L + 13 S $ 4,000 (Component A) 6 L + 9 S $ 3,500 (Component B) L20 and S20Valencia Products make automobile radar detectors and assembles two models: LaserStop and SpeedBuster. Both models use the same electronic components. For the next month, the supply of these is limited to 4,000 of component A and 3,500 of component B. The number of each component required for each product, the profit per unit, and the resulting linear optimization model are given in the accompanying tables. Complete parts a through d, answering each question independently relative to the original problem. Click the icon to view the data table and linear optimization model. a. If the unit profit for SpeedBuster is decreased to $131, how will the optimal solution and profit change? The optimal solution when the profit for SpeedBuster is decreased to $131 is to produce LaserStop and SpeedBuster. This solution gives the | maximum possible profit, which is $ . This solution is the same as the original solution, because the number of LaserStop models produced has stayed the same and the number of SpeedBuster models produced as stayed the same. (Type integers or decimals rounded to two decimal places as needed.)