Sydney Water processes wastewater from 1.4 million households at Malabar Sewage Treatment Plant. This wastewater is...
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Sydney Water processes wastewater from 1.4 million households at Malabar Sewage Treatment Plant. This wastewater is treated by primary sedimentation, producing primary sludge of 5000 m³.day-¹. A representative sample of primary sludge was sent to Sydney Water analytical laboratories for characterisation and the following results were produced: Specific gravity: 1.022 Moisture fraction: 0.850 Volatile fraction of total solids: 0.761 Total BMP (measured over 20 days): 220 NmL.gVS-1 The following molar masses are provided: carbon (C) = 12.0 g/mol, hydrogen (H) = 1.00 g/mol, oxygen (O) = 16.0 g/mol, nitrogen (N) = 14.0 g/mol. All gasses have a molar volume (at standard temperature and pressure) of 22.4 L.mol-¹. (a) Assuming the digesters operate with 85% efficiency for volatile solids degradation, determine the daily mass of methane that may be produced. [10 Marks] (b) In addition to methane, describe the other major chemical product that will be produced by this anaerobic digestion process and determine the daily mass. [5 Marks] Gravitational acceleration: g = 9.81 m.s (D₁-D₂) P BOD, =BOD (1-ek) (D-D₂)-(B₁-B₂)f BOD, P Alkalinity (eq/L) = [HCO;]+2 [CO]+[OH-]-[H] h₂ dN dt == = -KN BS N₁ = No e-kt Δπ = 2g AC₁ = Fw = Kw (APa - Aπ) = BOD, VsL= F/M == +c] 鬥 G + Cc - Cp 2 Mw Pw = (Mw + Ms) V (m/day) = 0.35 Ms SSIPPS 3 m CH. kg COD QSi XV -πp A V - = 9(Pp - Pw)d² 18μ E = Oc= Ms SSP 4x (COD₁ - COD) volume of sample volume of sample plus dilution water pH = -log10[H+] COD COD(m²) = 8000(B − A)[Normality of FAS] V = (C₁-C₂), C₁ APa S 9(Sp-1)d² Vs 18v = = XV (Q-Qw) Xe + Qw Xr = -x100 My Mf + Sup Sfp Msl Mw Ms SslP SwP Ssp h₁ = V(a+bV) x Q 2 V = [3.3 g(Sp-1)d] [Pr + Pc-Pp + h₁ = f' _I (1-8) V² Ød £³ g U= G= 0.5 F₁ = K₁AC₁ = = R(%): Q(Si - Se) XV Cf-Cp Cf P HK QpCp A -X 100 P₁ = (1 - Pw) = (Mw + Ms) P = EQ₁ × TS₁ x VS₁ × BMP₁ Sydney Water processes wastewater from 1.4 million households at Malabar Sewage Treatment Plant. This wastewater is treated by primary sedimentation, producing primary sludge of 5000 m³.day-¹. A representative sample of primary sludge was sent to Sydney Water analytical laboratories for characterisation and the following results were produced: Specific gravity: 1.022 Moisture fraction: 0.850 Volatile fraction of total solids: 0.761 Total BMP (measured over 20 days): 220 NmL.gVS-1 The following molar masses are provided: carbon (C) = 12.0 g/mol, hydrogen (H) = 1.00 g/mol, oxygen (O) = 16.0 g/mol, nitrogen (N) = 14.0 g/mol. All gasses have a molar volume (at standard temperature and pressure) of 22.4 L.mol-¹. (a) Assuming the digesters operate with 85% efficiency for volatile solids degradation, determine the daily mass of methane that may be produced. [10 Marks] (b) In addition to methane, describe the other major chemical product that will be produced by this anaerobic digestion process and determine the daily mass. [5 Marks] Gravitational acceleration: g = 9.81 m.s (D₁-D₂) P BOD, =BOD (1-ek) (D-D₂)-(B₁-B₂)f BOD, P Alkalinity (eq/L) = [HCO;]+2 [CO]+[OH-]-[H] h₂ dN dt == = -KN BS N₁ = No e-kt Δπ = 2g AC₁ = Fw = Kw (APa - Aπ) = BOD, VsL= F/M == +c] 鬥 G + Cc - Cp 2 Mw Pw = (Mw + Ms) V (m/day) = 0.35 Ms SSIPPS 3 m CH. kg COD QSi XV -πp A V - = 9(Pp - Pw)d² 18μ E = Oc= Ms SSP 4x (COD₁ - COD) volume of sample volume of sample plus dilution water pH = -log10[H+] COD COD(m²) = 8000(B − A)[Normality of FAS] V = (C₁-C₂), C₁ APa S 9(Sp-1)d² Vs 18v = = XV (Q-Qw) Xe + Qw Xr = -x100 My Mf + Sup Sfp Msl Mw Ms SslP SwP Ssp h₁ = V(a+bV) x Q 2 V = [3.3 g(Sp-1)d] [Pr + Pc-Pp + h₁ = f' _I (1-8) V² Ød £³ g U= G= 0.5 F₁ = K₁AC₁ = = R(%): Q(Si - Se) XV Cf-Cp Cf P HK QpCp A -X 100 P₁ = (1 - Pw) = (Mw + Ms) P = EQ₁ × TS₁ x VS₁ × BMP₁
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An Introduction to Statistical Methods and Data Analysis
ISBN: 978-1305269477
7th edition
Authors: R. Lyman Ott, Micheal T. Longnecker
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