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Question $3$ of $5$

Given the series

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(n!{)}^3}{(6n)!}$

find the ratio $|\frac{a_{n1}}{a_n}|.$

$($Express numbers in exact form. Use symbolic notation and fractions where needed.$)$

$|\frac{a_{n1}}{a_n}|=\sqrt[\phantom{2}]{\frac{(n1{)}^3}{(6n6)(n5)(6n4)(6n3)(6n2)(6n1)}}$

Incorrect Answer

Use the Ratio Test to determine the correct statement.

$$ The Ratio Test is inconclusive.

The series diverges.

The series converges.

Correct Answer