Question: CKN: 3 0 5 6 0 3 . ( a ) A TCP sender , called Ois n , and a TCP receiver, called Niamh,

CKN: 30560
3.(a) A TCP sender, called Oisn, and a TCP receiver, called Niamh, communicate over a
connection, in which segment loss is possible. Oisin's goal is to send ten segments to
Niamh. Oisin sends an initial window of five segments at times t =1,2,3,4 and 5
respectively.
The initial value of the sequence number used by Oisin is 69. Every segment sent to the
Niamh contains 975 bytes.
The delay between Oisin and Niamh is 7 time units. For example, the first segment
arrives at Niamh's TCP at time t =8 units. The ACK corresponding to this segment
arrives at time t =15.
Three of the five segments are lost between Oisin and Niamh. None of the ACKs are
lost. No timeouts occur, and any out of order segments received are thrown out.
Oisin
t=1
t=2
t=3
t=4
t=5
Niamh
Oisin segment
Oisin segment
Oisig segment
Oisin segment
Oisin segment
Ack sek
Ack seg
t=9
t =10
t=11
t =12
t=1
t =16
t=17
t=18
t =19
Figure 6: TCP Sender and Receiver.
(i) What are the sequence numbers of the segments sent at times t =1,2,3,4 and
t =5?
(ii) What are the values of the ACK numbers sent at times t =8,9,10,11 and t =12?
(If the corresponding segment is lost, respond by writing "x")
(iii) What are the sequence numbers of the segments sent at times t =15,16,17,18
and t =19?(If and ACK never arrives, give "x" as your answer)
[10 Marks]

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