Cl2 = 2C1 (6-12a) h-1 +01: + CO co e CICO (6-126) CICO + Cl2 CI,CO + CI (6-12c) Show that the rate predicted by the reaction mechanism 6-12a-c, with the second step assumed to be rate-limiting and the first step assumed to be at equilibrium, is rate = kg K 1/2(Cl2]1/2[CO). Show that the initial rate law predicted by the reaction mechanism 6-12a-c, with the first step rate-limiting, is rate = 2k1(Cl2]. Assume that the Cl produced in step (3) can be neglected initially