Class Management | Help Homework 7 Begin Date: 10/17/2022 9:00:00 AM -- Due Date: 10/31/2022 11:59:00 PM End Date: 10/31/2022 11:59:00 PM (6%) Problem 2: Suppose a person does 1.25 x 10 J of useful work in 8.25 h. A 50% Part (a) What is the average useful power output, in watts, of the person? P= cancel notext cos() tan() 7 8 9 HOME cotan() asin() acos() E 5 6 atan( acotan() sinh() 1 2 3 cosh( tanh() cotanh() + END Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 2% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback. 4 50% Part (b) Working at this rate, how long, in seconds, will it take this person to lift 2100 kg of bricks 1.65 m to a platform? (Work can be omitted because it is not considered useful output.)Class Management I Help Homework 7 Begin Date: 10/17/2022 9:00:00 AM -- Due Date: 10/31/2022 11:59:00 PM End Date: 10/31/2022 11:59:00 PM (6%) Problem 3: Suppose a shot-putter who takes it = 1.35 s to accelerate the m = 7.35-kg shot from rest to v = 12.5 m/s raises it h = 0.725 m during the process. A 50% Part (a) What is the power output P, of the shot-putter, in terms of g (the acceleration due to gravity) and the variables given in the problem statement. (Do not include the power required to accelerate his body.) Grade Summary P = I cancel % Deductions notext Potential 1' a 6 6 l ( 7 9 l | Submissions . . a b d | 4 5 6 | | E'ltengzisargenggng g h j I 1 2 3 | l dEiIed View k m P | + - 0 . | l S t v E J Submit Him I give up! Hints: deduction per hint. Hints remaining: _ Feedback: deduction per feedback. A 50 % Part (b) Calculate the power output, in watts, of the shot-putter. (Do not include the power produced to accelerate his body.)