Question: clear; clc b(1) = 2; c = 1:3:8; counter 3; for n = 1:3 m(n) = b(n+1) -counter; b(n) -3*C (4-n); n = end

 clear; clc b(1) = 2; c = 1:3:8; counter 3; for

clear; clc b(1) = 2; c = 1:3:8; counter 3; for n = 1:3 m(n) = b(n+1) -counter; b(n) -3*C (4-n); n = end

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