Question: Closure in Reverse [ 7 points ] Suppose that L is an arbitrary regular language. Prove that L R , the reverse of L ,

Closure in Reverse [7 points]
Suppose that L is an arbitrary regular language. Prove that L
R, the reverse of L, is also regular.
If a string w is in L, the reverse of that string, w
R, is in L
R. The reverse operation is defined recursively as:
\epsi
R =\epsi
For a string w and symbol a in \Sigma ,(wa)
R = a(w
R)
i.e.(110)R =011.

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