Question: Code 1: if (number % 2 == 0) even = true; else even = false; Code 2: even = (number % 2 == 0) ?

 Code 1: if (number % 2 == 0) even = true;

Code 1: if (number % 2 == 0) even = true; else even = false; Code 2: even = (number % 2 == 0) ? true: false; Code 3: even = number % 2 == 0; Code 2 has a compile error, because you cannot have true and false literals in the conditional expression. Code 3 has a compile error, because you attempt to assign number to even. All three are correct, but Code 1 is preferred. All three are correct, but Code 2 is preferred. All three are correct, but Code 3 is preferred. Give it another try

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