Question: code class = asciimath > B - 2 . ( 4 0 pts ) E = 2 4 0 GPa,A = 2 times 1

code class="asciimath">B-2.(40 pts) E=240GPa,A=2\times 10^(-4)m^(2) for elements 1 and 3, and A=4\times 10^(-4)m^(2) for element 2. Note that the roller boundary condition means that the corresponding node stays on the surface without any separation or penetration.
code class = "asciimath" > B - 2 . ( 4 0 pts ) E

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