Question: code class = asciimath > Is this approximation an overestimate or an underestimate? L ( x ) = h ( 2 ) + h ^

code class="asciimath">Is this approximation an overestimate or an underestimate? L(x)=h(2)+h^(')(2)(x-2)=2^(3)+3*2^(2)(x-2)=8+12(x-2)(2.1)^(3)=n(2.1) ~~L(2.1)=8+12(2.1-2)=8+12(.1)=8+1.2=9.2 underestimate since L(x)(I understand how the answer was gotten. But could you please explain why it was either an underestimate or an overestimate? I don't know what that means.)
code class = "asciimath" > Is this approximation

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