Question: Code for 1-pass of Radixsort using conventional 2-array approach 1 for(1-0 radix; i++) 2 while (!lst_is_empty (fromi]) /I dequeue elements in fromi] x = 1st-pop-front

![radix; i++) 2 while (!lst_is_empty (fromi]) /I dequeue elements in fromi] x](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f552f964776_59366f552f90b5d4.jpg)
![= 1st-pop-front (from [i]); digit = (x/divisor)%radix; lst_push_back (to[digit], x); 4 6](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f552f9e3d57_59366f552f98eeba.jpg)
Code for 1-pass of Radixsort using conventional 2-array approach 1 for(1-0 radix; i++) 2 while (!lst_is_empty (fromi]) /I dequeue elements in fromi] x = 1st-pop-front (from [i]); digit = (x/divisor)%radix; lst_push_back (to[digit], x); 4 6 Professor Periwinkde thinks that just one array of dimension radix is sufficient and proposes the following code instead to perform a single pass with just one array called buckets of dimension radix: Prof. Periwinkle's code for 1-pass of RadixSort using just one array 1 nt n; for(i-e; i
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