Question: code: #include void printHelp () { printf ( ); printf (a: a(x) = x*x ); printf (b: b(x) = x*x*x ); printf (c: c(x) =

code:

#include  void printHelp () { printf (" "); printf ("a: a(x) = x*x "); printf ("b: b(x) = x*x*x "); printf ("c: c(x) = x^2 + 2*x + 7 "); printf ("q: quit "); } void a(float x) { float v = x*x; printf (" a(%.2f) = %.2f^2 = %.2f ", x, x, v); } // end function a void b(float x) { float v = x*x*x; printf (" a(%.2f) = %.2f^3 = %.2f ", x, x, v); } // end function b void c(float x) { float v = x*x + 2*x + 7; printf (" c(%.2f) = %.2f^2 + 2*%.2f + 7 = %.2f ", x, x, x, v); } // end function c int menu () { char selection; float x; printHelp (); scanf ("%s", &selection); if (selection == 'q') return 1; scanf ("%f", &x); if (selection == 'a') a(x); if (selection == 'b') b(x); if (selection == 'c') c(x); return 0; } // end function menu int main() { while (menu() == 0); printf ("... bye ... "); return 0; } // end main

(x/2) Create a new function, shrink (float x), that would divide the input value by 2 using the shown code as a template. Support your experimentation with screen captures of executing the new code.

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